Answer:
- 0.07 °C
Explanation:
At constant pressure and number of moles, Using Charle's law
[tex]\frac {V_1}{T_1}=\frac {V_2}{T_2}[/tex]
Given ,
V₁ = 439 mL = 0.439 L ( 1 L = 0.001 mL )
V₂ = 0.378 L
T₁ = 317.15 K
T₂ = ?
Using above equation as:
[tex]\frac{0.439}{317.15}=\frac{0.378}{T_2}[/tex]
[tex]T_2=\frac{0.378\cdot \:317.15}{0.439}=273.08\ K[/tex]
The conversion of T(K) to T( °C) is shown below:
T( °C) = T(K) - 273.15
So, T = 273.08 - 273.15 °C = - 0.07 °C
