Answer
given,
current, I = 3.7 A
width of conductor = 1.5 cm
Length = 4 cm
thickness = 12 μm
hall potential difference = 78 μV
magnetic field = 0.76 T
a) drift velocity of the charge carrier
[tex]v_d = \dfrac{V_H}{Bd}[/tex]
[tex]v_d = \dfrac{78 \times 10^{-6}}{0.76 \times 0.015}[/tex]
[tex]v_d = 6.84 \times 10^{-3}\ m/s[/tex]
number density of charge carrier
[tex]n=\dfrac{I}{Aev_d}[/tex]
[tex]n=\dfrac{3.7}{0.015\times 12 \times 10^{-6}\times 1.6 \times 10^{-19}\times 6.84 \times 10^{-3}}[/tex]
n = 1.878 x 10²⁸ electrons/m³
