Respuesta :
Answer:
t=40s,
Explanation:
If you can swim in still water at 0.5m/s, the shortest time it would take you to swim from bank to bank across a 20m wide river, if the water flows downstream at a rate of 1.5m/s, is most nearly:
from the question the swimmer will have a velocity which is equal to the sum of the speed of the water and the velocity to swi across the bank
Vt=v1+v2
the time is takes to swim across the bank will be
DY=Dv*t
DY=distance across the bank
Dv=ther velocity of the swimmer across the bank
t=20/ 0.5m/s,
t=40s, time it takes to swim across the bank
velocity is the rate of displacement
displacement is distance covered in a specific direction
Answer:42.55 seconds
Explanation:
Check attached file for the diagram.
Vr= velocity of the river, if the water flows downstream, which is equal to 1.5m/s(from the question), Vb= my velocity at angle alpha which is perpendicular to the x-axis, and c= distance to swim from river bank to the other river bank.
Therefore, the shortest time to be taken to swim or cross the river,t=river with width of C÷ vertical component Vj.
Note that (vector) Vj= (vector)Vr+(vector)Vb.
Also, alpha must be maximum and for that to happen it must have a value of one(1).
Hence, time taken to cross the river,t= C/Vb× sin (alpha).
t= 20m÷ 0.5 ×sin 90.
t= 20÷ 0.47.
t= 42.55 seconds.
