Answer:
C. 180 N
Explanation:
[tex]m[/tex] = mass of the blocking sled = 60 kg
[tex]\mu[/tex] = Coefficient of kinetic friction = 0.30
[tex]f[/tex] = kinetic frictional force acting on the sled
kinetic frictional force acting on the sled is given as
[tex]f = \mu mg = (0.30) (60) (10) = 180 N[/tex]
[tex]F[/tex] =Force applied
For the sled to move at constant speed, the applied force must be same as the frictional force
[tex]F = f\\F = 180 N[/tex]