Answer:
The linear density of the spring = 0.00675 kg/m
Explanation:
F₀ = 1/λ[tex]\sqrt{T/D}[/tex]........................ Equation 1
Making D the subject of formula in equation 1,
D = T/(F₀λ)²................................... Equation 2
Where F₀ = Frequency of the string, T = Tension, D = linear Density, λ = Wave length.
Given: T = 907 N, λ = 1.40 m
F₀ = 1/t, where t = period and t = 3.82 ms = 3.82 × 10⁻³ s
F₀ = 1/(3.82×10⁻³) = 10³/3.82 = 261.78 Hz.
Substituting these values into equation 2
D = 907/(1.4×261.78)²
D = 907/(366.492)²
D = 907/134316.39
D = 0.00675 kg/m
The linear density of the spring = 0.00675 kg/m
