Answer:
A.[tex]28x+32y<7500[/tex]
B.199 hours
Step-by-step explanation:
Let carpenters work for x hours and painters work for y hours.
Nelson must spend money <$7500
Carpenters charge per hour=$28
Painters charge per hour=$32
A.We have to write inequalities which represents this situation
According to question
[tex]28x+32y<7500[/tex]
B.If hires carpenters work for total time=40 hours
We have to find the maximum number of hours for which painters can work without exceeding the budget.
Substitute the value in above inequality equation then, we get
[tex]28(40)+32y<7500[/tex]
[tex]1120+32y<7500[/tex]
Subtracting 1120 on both sides
[tex]32y<7500-1120[/tex]
[tex]32y<6380[/tex]
Divide by 32 on both sides then we get
[tex]y<\frac{6380}{32}[/tex]
[tex]y<199.375[/tex]
Hence,painters can work for maximum 199 hours.
