A trapeze artist, with swing, weighs 800 N; he is momentarily heldto one side by his partner using a horizontal force so that theswing ropes make an angle of 30o with thevertical. In such a condition of static equilibrium, what isthe horizontal force being applied by the partner?

Respuesta :

Answer:

461.88 N

Explanation:

[tex]F_{g}[/tex] = Weight of the swing = 800 N

[tex]T[/tex] = Tension force in the rope

[tex]F[/tex] = Horizontal force being applied by the partner

Using equilibrium of force in vertical direction using the force diagram, we get

[tex]T Cos30 = F_{g}\\T Cos30 = 800\\T = \frac{800}{Cos30} \\\\T = 923.76 N[/tex]

Using equilibrium of force in horizontal direction using the force diagram, we get

[tex]F = T Sin30\\F = (923.76) (0.5)\\F = 461.88 N[/tex]

Ver imagen JemdetNasr

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, The horizontal force being applied by the partner will be 461.88 N.

What is force?

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

The given data in the problem will be;

W is the weight of the swing = 800 N

T is the tension force in the rope

F is the horizontal force being applied by the partner =?

By balancing the vertical forces;

[tex]\rm Tcos30^0= F_g \\\\ \rm Tcos30^0= 800 \\\\ \rm T= \frac{800}{cos30^0} \\\\ \rm T=927.36 N[/tex]

By balancing the horizontal forces;

[tex]\rm F= T sin 30^0 \\\\ \rm F= 923.76 \times sin 30^0 \\\\ \rm F= 461.88 N[/tex]

Hence the horizontal force being applied by the partner will be 461.88 N.

To learn more about the force refer to the link;

https://brainly.com/question/26115859