Answer:
70 cm
Explanation:
0.5 kg at 20 cm
0.3 kg at 60 cm
x = Distance of the third 0.6 kg mass
Meter stick hanging at 50 cm
Torque about the support point is given by (torque is conserved)
[tex]0.5(50-20)=0.3(60-50)+0.6x\\\Rightarrow x=\dfrac{0.5(50-20)-0.3(60-50)}{0.6}\\\Rightarrow x=20\ cm[/tex]
The position of the third mass of 0.6 kg is at 20+50 = 70 cm
Answer:
70 cm mark
Explanation:
m1 = 0.5 kg
m2 = 0.3 kg
m3 = 0.6 kg
let the third mass is at d cm from 50 cm mark. take moments about the 50 cm mark.
Anticlockwise torque = clock wise torque
0.5 x ( 50 - 20) + 0.6 x d = 0.3 (60 - 50)
0.5 x 30 + 0.6 d = 0.3 x 10
15 + 0.6 d = 3
0.6 d = - 12
d = - 20 cm
So, it means third mass is at 20 cm right to the 50 cm mark. So, it is at 70 cm mark.
