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For a demonstration, a professor uses a razor blade to cut a thin slit in a piece of aluminum foil. When she shines a laser pointer (λ=680nm) through the slit onto a screen 5.5 m away, a diffraction pattern appears. The bright band in the center of the pattern is 8.0 cm wide. What is the width of the slit? answer in mm.

Respuesta :

Answer:

width of the slit = a = 0.0935 mm

Explanation:

width of central maximum for single slit diffraction is:

[tex]w=\frac{2 \lambda L}{a}[/tex] ----- (1)

Distance between source and screen = L = 5.5 m

Width of bright band = w = 8 cm

                                   = 0.08 m

                               λ = 680 nm

Width of the slit = a = ?

Arranging (1) for a

                              [tex]a=\frac{2 \lambda L}{w}[/tex]

[tex]a=\frac{2 (680 \times 10^{-9})(  5.5)}{.08}\\a = 93.5 \mu m[/tex]

                                     a = 0.0935 mm

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