Answer:
0.05269 m
Explanation:
[tex]m_2[/tex] = Mass of play doh thrown = 0.085 kg
[tex]m_1[/tex] = Hanging mass of play doh = 0.45 kg
v =Combined velocity
u = Speed of play doh = 6.4 m/s
As the momentum of the system is conserved we have
[tex]m_2u=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_2u}{m_1+m_2}\\\Rightarrow v=\dfrac{0.085\times 6.4}{0.45+0.085}\\\Rightarrow v=1.01682\ m/s[/tex]
Height of the combined mass is given by
[tex]h=\dfrac{v^2}{2g}\\\Rightarrow h=\dfrac{1.01682^2}{2\times 9.81}\\\Rightarrow h=0.05269\ m[/tex]
The height to which the combined mass will rise is 0.05269 m
