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A hydraulic lift is used to lift a heavy box that is pushing down on a 3.0m2 piston with a force of 1500 N. What force needs to be exerted on a 0.08 m2 piston to lift the box?

Respuesta :

Answer:

40 N

Explanation:

[tex]F_1[/tex] = Force on piston = 1500 N

[tex]A_1[/tex] = Area of the first piston = 3 m²

[tex]A_2[/tex] = Area of the second piston = 0.08 m²

[tex]F_2[/tex] =  Force on the second piston

From Pascal's law we have

[tex]\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\Rightarrow F_2=\dfrac{F_1A_2}{A_1}\\\Rightarrow F_2=\dfrac{1500\times 0.08}{3}\\\Rightarrow F_2=40\ N[/tex]

The force that is needed to lift the box is 40 N