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Using your best estimates, how many times would you have to slap a 1 kg rotisserie chicken in order to cook it? You can assume the chicken is mostly water, starts at 0 ∘C, and that it must reach an internal temperature of 170∘ F in order to be cooked.

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Manetho

Answer:

n= 16021.03 slaps

Explanation:

Using law of Energy conservation

E_{thermal}= Kinetic energy of hand

⇒[tex]mc\Delta T= n\frac{1}{2}m_hv_h^2[/tex]

m_h= mass of the hand = 0.4 kg

v_h= velocity of the hand = 10 m/s

n= number of slaps

c= 4180 J/Kg °C

m= mass of chicken = 1 kg

Assuming all the energy of hand goes into chicken

Given Ti=0°C and T_f= 170 F= 76.66°C

Now putting the values in above equation to get n

[tex]1\times4180(76.66)= n\frac{1}{2}0.4\times10^2[/tex]

n= 16021.03 slaps

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