To solve this problem we will apply the concept related to Intensity, that is, the acoustic power transferred by a sound wave per unit of normal area to the direction of propagation:
[tex]I = \frac{P}{A} \rightarrow P= AI[/tex]
Where,
P = Power
A = Acoustic Area
Our values are given as,
r= 12 m
[tex]I = 4.3*10^{-3} W/m^2[/tex]
The Area then would be
[tex]A = 4\pi r^2[/tex]
[tex]A = 4\pi (12)^2[/tex]
[tex]A = 1809.55m^2[/tex]
Replacing the values we have that
[tex]P = (4.3*10^{-3} W/m 2)(1809.55m^2 )[/tex]
[tex]P = 7.781 W[/tex]
The total sound power P emitted by the source is 7.781W
