Answer:
2.28%
Step-by-step explanation:
given that the height, in inches, of a 25-year-old man is a normal random variable with parameters = 71 and variance = 6:25.
If X is the height of 25 year old man then X is N(71, 2.5)
a) Probability of men in the 6-footer club are over 6 feet, 5 inches
=[tex]P(X>6'5")\\=P(X>77")\\= P(Z>\frac{77-72}{2.5} \\=P(X>2)[/tex]
= 0.0228
percentage of men in the 6-footer club are over 6 feet, 5 inches
100 times prob
=2.28%
2.28% of men in the 6-footer club are over 6 feet, 5 inches willbe taller than 6 feet and 5 inches
