To solve this problem we will apply the continuity and pressure and temperature ratio equations defined as
[tex]\frac{P_1}{P_2} = \frac{T_1}{T_2}[/tex]
This relationship warns us that there is a proportionality between the pressure and the temperature of state one, compared to the same variables in state two.
Our values are given as,
[tex]P_1 = 0.7atm[/tex]
[tex]T_1 = 1*10^2\°C = 100\°C[/tex]
PART A ) Rearranging to find the Temperature we have,
[tex]T_2 = \frac{P_2}{P_1}T_1[/tex]
[tex]T_2 = \frac{0.040}{0.7}(100+273.15)[/tex]
[tex]T_2 = 21.32K[/tex]
[tex]T_2 = -251.8\°C[/tex]
Therefore the temperature when the pressure is 0.04atm would be
PART B) Using the same relation but now we will find the pressure:
[tex]P_2 = P_1 \frac{T_2}{T_1}[/tex]
[tex]P_2 = 0.7(\frac{450+273.15}{100+273.15})[/tex]
[tex]P_2 = 1.35atm[/tex]
Therefore the pressure at 450°C is 1.35atm
