Answer:
A=0.1024 m
Explanation:
Given Data
M=3.60 kg
m=42.0 g=0.042 kg
v₀=140 m/s
k=560 N/m
To find
Amplitude of Simple Harmonic Motion
Solution
Use conservation of momentum to solve for velocity
[tex]mv=(m+M)V\\V=\frac{mv}{m+M}\\ V=\frac{0.042kg*140m/s}{0.042kg+3.60kg}\\ V=1.6145 m/s[/tex]
Use conservation of energy to solve for amplitude
ΔKE+ΔUg+ΔUs=0
ΔKE+0+ΔUs=0
1/2MV²-1/2kA²=0
[tex]A=\sqrt{\frac{MV^{2} }{k} }\\ A=\sqrt{\frac{(3.642kg)*(1.6145m/s)}{560N/m} }\\ A=0.1024m[/tex]
