Determine whether the two given lines l1 and l2 are parallel, skew, or intersecting. If they intersect, find the point of intersection. l1 :    x = t y = 1 + 2t z = 2 + 3t l2 :    x = 3 − 4s y = 2 − 3s z = 1 + 2s 2.

Respuesta :

Answer:

Skew lines

Step-by-step explanation:

Two lines are given and we have to find out whether they are parallel, skew, or intersecting

[tex]x =t , y = 1 + 2t, z = 2 + 3t, l2 : \\ x = 3 -4s,, y = 2 -3s, z = 1 + 2s[/tex]

direction ratios of these two lines are

(1,2,3) and (-4, -3,2) (coefficient of parameters)

Obviously these two are neither equal nor proportional

Hence we get not parallel lines.  If these intersect there must be a common point making

[tex]t= 3-4s:   1+2t =2-3s and 2 + 3t =1+2s[/tex]

Consider first two equation

[tex]t+4s =3\\2t+3s = 1\\2t+8s = 6\\-5s =-5\\s=1[/tex]

when s=1, t = -1

Let us check whether these two values satisfy the third equation

2+3t = -1 and 1+2s = 1+2 =3

Not equal.  so there is no common point between them

These two are skew lines