Respuesta :
Answer
given,
Electric field,E = 490 N/C
time, t = 54 ns
for electron
Mass of electron me = 9.1 x 10⁻³¹ kg
Charge of electron e = -1.6 x 10⁻¹⁹ C
electrostatic force
F = E q
F = 490 x 1.6 x 10⁻¹⁹
F = 784 x 10⁻¹⁹ N
now, using newton second law
[tex]a = \dfrac{784\times 10^{-19}}{9.1\times 10^{-31}}[/tex]
a = 8.62 x 10¹² m/s²
using equation of motion
v = u + a t
v = 0 + 8.62 x 10¹² x 54 x 10⁻⁹
v = 4.65 x 10⁵ m/s
velocity of electron is equal to v = 4.65 x 10⁵ m/s
For Proton
Mass mp = 1.67 x 10⁻²⁷ kg
Charge p = 1.6 x 10⁻¹⁹ C
Electric field E = 490 V/C
from above solution
F = 784 x 10⁻¹⁹ N
now, acceleration
[tex]a = \dfrac{784\times 10^{-19}}{1.67\times 10^{-27}}[/tex]
a = 4.69 x 10¹⁰ m/s²
using equation of motion
v = u + a t
v = 0 + 4.69 x 10¹⁰ x 54 x 10⁻⁹
v = 4.65 x 10³ m/s
velocity of electron is equal to v = 4.65 x 10³ m/s
Answer:
Explanation:
Electric field, E = 490 N/C
mass of electron, me = 9.1 x 10^-31 kg
mass of proton, mp = 1.67 x 10^-27 kg
charge of electron or proton = 1.6 x 10^-19 C
time, t = 54 ns = 54 x 10^-9 s
initial velocity, u = 0 m/s
Force on each particle, F = q E = 1.6 x 10^-19 x 490 = 7.84 x 10^-17 N
acceleration of electron = Force / mass of electron
ae = (7.84 x 10^-17) / ( 9.1 x 10^-31) = 8.6 x 10^13 m/s²
Let the velocity of electron is ve.
use first equation of motion
ve = u + ae x t
ve = 0 + 8.6 x 10^13 x 54 x 10^-9
ve = 4.65 x 10^6 m/s
acceleration of proton = Force / mass of proton
ap = (7.84 x 10^-17) / ( 1.67 x 10^-27) = 4.69 x 10^10 m/s²
Let the velocity of electron is vp.
use first equation of motion
vp = u + ap x t
vp = 0 + 4.69 x 10^10 x 54 x 10^-9
ve = 2535.1 m/s
