Answer:
398.22 kg
Explanation:
[tex]m_1[/tex] = Mass of canoe 1 = 320 kg
[tex]m_2[/tex] = Mass of canoe 2
[tex]v_1[/tex] = Velocity of canoe 1 = 0.56 m/s
[tex]v_2[/tex] = Velocity of canoe 2 = 0.45 m/s
In this system the linear momentum is conserved
[tex]m_1v_1=m_2v_2\\\Rightarrow m_2=\dfrac{m_1v_1}{v_2}\\\Rightarrow m_2=\dfrac{320\times 0.56}{0.45}\\\Rightarrow m_2=398.22\ kg[/tex]
The mass of the second canoe is 398.22 kg
Answer:
398.22 kg
Explanation:
mass of I canoe, m1 = 320 kg
initial velocity of both the canoe = 0
final velocity of I canoe, v1 = 0.56 m/s
final velocity of II canoe, v2 = - 0.45 m/s
Let the mass of second canoe is m2.
Use conservation of momentum
momentum before push = momentum after push
0 + 0 = m1 x v1 + m2 x v2
0 = 320 x 0.56 - m2 x 0.45
m2 = 398.22 kg
Thus, the mass of second canoe is 398.22 kg.
