Respuesta :
a)The average acceleration of the car is [tex]1.4 \mathrm{m} / \mathrm{s}^{2}[/tex]
b) The distance travelled is 560 m
Explanation:
a) Acceleration is defined as the rate of change in velocity per unit time. So it can be obtained by measuring the ratio of speed to time.
[tex]Average acceleration =\frac{\text { Final speed - Initial Speed }}{\text { time }}[/tex]
Since here the initial speed was zero and final speed is given as 28 m/s, then time is given as 20 s. So,
[tex]\text {Acceleration}=\frac{28-0}{20}=\frac{28}{20}=1.4 \mathrm{m} / \mathrm{s}^{2}[/tex]
b) As the speed is given as 28 m/s, then
[tex]\text {distance}=\text { Speed } \times \text { Time }=28 \times 20=560 \mathrm{m}[/tex]
So the distance travelled is 560 m and average acceleration is [tex]1.4 \mathrm{m} / \mathrm{s}^{2}[/tex].
