The electron configuration for Boron (B) is given as [tex]1s^2 2s^2 2p^1[/tex] or [tex][He] 2s^2 2p^1[/tex]
Answer:
Boron (B) has an atomic number equal to 5 and is an element from Group 13 of the periodic table. It has a total of 5 electrons of which 3 are valence electrons.
The electron configuration for Boron can be written with the first two electrons in the 1s orbital. Since 1s orbital can hold only two electrons, out of the remaining three electrons; two electrons will go in the 2s orbital. The remaining one electron in the 2p orbital. Therefore the Boron electron configuration will be [tex]1s^2 2s^2 2p^1[/tex]
Since [tex]1s^2[/tex] is the electron configuration for Helium, Electron configuration for Boron can also be written as [tex][He] 2s^2 2p^1[/tex]
(Refer attached figure)
