A van starts off 191 miles directly north from the city of Morristown. It travels due east at a speed of 25 miles per hour. After travelling 119 miles, how fast is the distance between the van and Morristown changing?

Respuesta :

Answer:

Distance between the van and Morristown is changing at the rate of 13.22 miles per hour.

Step-by-step explanation:

From the figure attached,

Van starts from C (City of Morristown), reaches the point A 191 miles due North and then it travels with a speed of 25 miles per hour due East from A towards B.

We have to calculate the rate of change of distance BC, when the van reaches point B which is 119 miles away from A.

By Pythagoras theorem in the triangle ABC,

[tex]BC^{2}=AB^{2}+AC^{2}[/tex]

Distance AC is constant equal to 191 mi.

By differentiating the equation with respect to time 't'

[tex]2BC.\frac{d(BC)}{dt}=0+2AB.\frac{d(AB)}{dt}[/tex]

[tex]BC.\frac{d(BC)}{dt}=AB.\frac{d(AB)}{dt}[/tex]

Since BC² = (119)²+ (191)²

BC = √50642 = 225.04 miles

From the differential equation,

[tex](225.03).\frac{d(BC)}{dt}=119\times 25[/tex] [Since [tex]\frac{d(AB)}{dt}=25[/tex] miles per hour]

[tex]\frac{d(BC)}{dt}=13.22[/tex] miles per hour

Therefore, distance between the van and Morristown is changing at the rate of 13.22 miles per hour.

Ver imagen eudora