The velocity of the apple just before it hits the ground is 10 m/s.
The given parameters;
- mass of the apple, m = 0.2 kg
- potential energy of the apple, P.E = 10 J
Apply the principle of conservation of mechanical energy to determine the velocity of the apple before it hits the ground.
K.E = P.E
¹/₂mv² = 10
mv² = 2(10)
mv² = 20
0.2v² = 20
[tex]v^2 = \frac{20}{0.2} \\\\v^2 = 100\\\\v = \sqrt{100} \\\\v = 10 \ m/s[/tex]
Thus, the velocity of the apple just before it hits the ground is 10 m/s.
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