Answer:
[tex]8\mu C[/tex]
Explanation:
t = Time taken = [tex]2\mu s[/tex]
i = Current = 3 A
q(0) = Initial charge = [tex]2\mu C[/tex]
Charge is given by
[tex]q=\int_0^t idt+q(0)\\\Rightarrow q=\int_0^{2\mu s} 3dt+2\mu C\\\Rightarrow q=3(2\mu s-0)+2\mu C\\\Rightarrow q=6\mu C+2\mu C\\\Rightarrow q=8\mu C[/tex]
The magnitude of the net electric charge of the capacitor is [tex]8\mu C[/tex]