Answer:
The probability that she rolls a number greater that 4 or a 2 = [tex]\frac{1}{2}[/tex] or 50%
Step-by-step explanation:
Given:
A six sided number cube is rolled labelled from 1 to 6.
To find the probability that she rolls a number that is greater than 4 or a 2.
Solution:
The possible outcomes of rolling a six-sided cube are:
{1,2,3,4,5,6}
[tex]n(U)=6[/tex]
Event A:
The favorable outcomes greater than 4 are:
{5,6}
[tex]n(A)=2[/tex]
Probability of event A to occur = [tex]\frac{n(A)}{n(U)}=\frac{2}{6}[/tex]
Event B:
The favorable outcome is a 2
{2}
[tex]n(B)=1[/tex]
Probability of event B to occur = [tex]\frac{n(B)}{n(U)}=\frac{1}{6}[/tex]
We find that the two events are mutually exclusive as they have no common outcomes.
Thus, the probability that event A or B occurs ( P(AUB) ) can be given as:
⇒ [tex]\frac{2}{6}+\frac{1}{6}[/tex]
Since denominators same, so we add the numerators.
⇒ [tex]\frac{3}{6}[/tex]
Reducing it to simpler fraction:
⇒ [tex]\frac{1}{2}[/tex] (Answer)
Thus, the probability that she rolls a number greater that 4 or a 2 = [tex]\frac{1}{2}[/tex] or 50%
