Respuesta :
Answer:
The pressure exerted by this man on ground
(a) if he stands on both feet is 8.17 KPa
(b) if he stands on one foot is 16.33 KPa
Explanation:
(a)
When the man stand on both feet, the weight of his body is uniformly distributed around the foot imprint of both feet. Thus, total area in this case will be:
Area = A = 2 x 480 cm²
A = 960 cm²
A = 0.096 m²
The force exerted by man on his area will be equal to his weight.
Force = F = Weight
F = mg
F = (80 kg)(9.8 m/s²)
F = 784 N
Now, the pressure exerted by man on ground will be:
Pressure = P = F/A
P = 784 N/0.096 m²
P = 8166.67 Pa = 8.17 KPa
(b)
When the man stand on one foot, the weight of his body is uniformly distributed around the foot imprint of that foot only. Thus, total area in this case will be:
Area = A = 480 cm²
A = 0.048 m²
The force exerted by man on his area will be equal to his weight, in this case, as well.
Force = F = Weight
F = mg
F = (80 kg)(9.8 m/s²)
F = 784 N
Now, the pressure exerted by man on ground will be:
Pressure = P = F/A
P = 784 N/0.048 m²
P = 16333.33 Pa = 16.33 KPa
The pressure exerted by man is 8.17 KPa and 16.33 KPa
Case; 1
Area when man stand with two legs = 2 x 480 cm²
Area when man stand with two legs = 960 cm²
Area when man stand with two legs = 0.096 m²
Force = mg
Force = (80 kg)(9.8 m/s²)
Force = 784 N
Pressure = Force/Area
Pressure = 784 N/0.096 m²
Pressure = 8.17 KPa
Case; 2
Pressure = Force/Area
Pressure = 784 N/0.048 m²
Pressure = 16333.33 Pa
Pressure = 16.33 KPa
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