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The exponential functions y=(1-25)^x-2/5. -10 is shown hraphed along woth the horizontal line y=115 their intersection is (a,115) start by using wht they give you for the point of intersection ans substitute that into the given equation

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olatunjiolorundare20

Answer:26

Step-by-step explanation:

Y=1.25^x-2/5-10

Take log of both sides

So Y+10=1.25^x-2/5

So log to base 10 of the two sides of the equation is

Log(Y+10)=X-2/5log1.25.

To make X the subject, divide both sides by log1.25.

Log(Y+10)/log1.25=X-2/5.

Recall that Y was given to be 115

It becomes log(115 +10)/Log1.25=x-0.4

21.64=x-0.4

X=25.6

abidemiokin

The value of x from the given equation is 25.6

Logarithm of functions

Given the function y expressed as:

[tex]y=1.25^x-2/5-10[/tex]

Take logarithm of both sides to have:

[tex]y+10=1.25^x-2/5[/tex]

[tex]log(y+10)=x-2/5log1.25.[/tex]

Next is to make X the subject by dividing both sides by log1.25.

[tex]Log(y+10)/log1.25=x-2/5.[/tex]

[tex]log(115 +10)/log1.25=x-0.4[/tex]

[tex]21.64=x-0.4x=25.6[/tex]

Hence the value of x from the given equation is 25.6

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