A chemist adds 180.0 mL of a 1.42M sodium carbonate (Na CO,) solution to a reaction flask. Calculate the millimoles of sodium carbonate the chemist has added to the flask. Round your answer to 3 significant digits. mmol

Respuesta :

Answer: The millimoles of sodium carbonate the chemist has added to the flask are 256

Explanation:

Molarity is defined as the number of moles dissolved per liter of the solution.

To calculate the number of moles for given molarity, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{milli moles of solute}}{\text{Volume of solution in ml}}[/tex]     .....(1)

Molarity of [tex]BaCl_2[/tex] solution = 1.42 M

Volume of solution = 180.0 mL

Putting values in equation 1, we get:

[tex]1.42M=\frac{\text{milli moles of }BaCl_2}{180.0ml}\\\\\text{milli moles of }BaCl_2}={1.42M\times 180.0ml}=256milli mol[/tex]

Thus the millimoles of sodium carbonate the chemist has added to the flask are 256.