Answer:
1052
Step-by-step explanation:
The two given boxes for reference are presented below.
Since we know the dimensions of the first container, we can calculate its volume.
[tex]V_1= 5 \text{cm} \cdot 4 \text{cm} \cdot 4 \text{cm} = 80 \text{cm}^3[/tex]
The first container held 192 skittles. Using that fact, now that we know the volume of the first box, we can calculate the volume of a single skittle.
[tex]v = \frac{80}{192} = 0.416 \approx 0.42 \text{cm}^3[/tex]
The second container held 258 skittles.
The volume of the second box is:
[tex]V_2 = 12 \text{cm}\cdot 3 \text{cm} \cdot 3 \text{cm} = 108 \text{cm}^3[/tex]
Using this facts, the volume of a single skittle would be
[tex]v = \frac{108}{258} = 0.418 \approx 0.42 \text{cm}^3[/tex]
Therefore, the volume of single skittle is around to 0.42 cm³.
A skittle jar is a cylinder. Its volume is calculated by the formula
[tex]V = r^2h \pi[/tex],
where [tex]r[/tex] is the radius and [tex]h[/tex] is the height. From the given data, we have [tex]r = 3.15 \text{cm}[/tex] and [tex]h = 11.5 \text{cm}[/tex]. Hence, the volume of the jar is
[tex]V = 3.5^2 \cdot 11.5 \cdot 3.14 = 442 \text{cm}^3[/tex]
Now, we can determine the number of skittles in the jar. Let [tex]n[/tex] be the number of skittles in the jar. Then,
[tex]n = \frac{\text{volume of the jar}}{\text{volume of a skittle}} = \frac{V}{v} = \frac{442}{0.42} = 1052.38 \approx 1052\\[/tex]
