Respuesta :
Answer:
0.015 or 1.5 cm
Explanation:
From hook's law,
F = ke.................. Equation 1
Where F = Force, k = force constant of the rubber, e = extension of the rubber.
k = F/e................... Equation 2
e = F/k.................. Equation 3
Given: F = 2 N, e = 1 cm = 0.01 m
Substitute into equation 2
k = 2/0.01
k = 200 N/m.
(a) When the force = 3 newton, I.e
F = 3 N, k = 200 N/m
Substitute into equation 3
e = 3/200
e = 0.015
e = 0.015 m or 1.5 cm.
Thus the force will stretch the rubber band by 0.015 m or 1.5 cm
A force of 3N will stretch the rubber a distance of 0.015 m.
From Hookes's law, as long as the elastic limit is not exceeded the extension is directly proportional to the force applied.
F = Ke
F = force
K = force constant
e = extension
So;
2 N = K(1 × 10^-2) m
K = 2 N /(1 × 10^-2) m
K = 200 N/m
Hence;
3N = 200 N/m × a
Where a is the extension in meters
a = 3N/200 N/m
a = 0.015 m
Learn more about Hookes's law: https://brainly.com/question/3355345