Stretched 1 cm beyond its natural length, a rubber band exerts a restoring force of magnitude 2 newtons. Assuming that Hooke's Law applies, answer the following questions:(a) How far (in units of meters) will a force of 3 newtons stretch the rubber band?

Respuesta :

Answer:

0.015 or 1.5 cm

Explanation:

From hook's law,

F = ke..................  Equation 1

Where F = Force, k = force constant of the rubber, e = extension of the rubber.

k = F/e................... Equation 2

e = F/k.................. Equation 3

Given: F = 2 N, e = 1 cm = 0.01 m

Substitute into equation 2

k = 2/0.01

k = 200 N/m.

(a) When the force = 3 newton, I.e

F = 3 N, k = 200 N/m

Substitute into equation 3

e = 3/200

e = 0.015

e = 0.015 m or 1.5 cm.

Thus the force will stretch the rubber band by 0.015 m or 1.5 cm

A force of 3N will stretch the rubber a distance of 0.015 m.

From Hookes's law, as long as the elastic limit is not exceeded the extension is directly proportional to the force applied.

F = Ke

F = force

K = force constant

e = extension

So;

2 N = K(1 × 10^-2) m

K = 2 N /(1 × 10^-2) m

K = 200 N/m

Hence;

3N = 200 N/m × a

Where a is the extension in meters

a = 3N/200 N/m

a = 0.015 m

Learn more about Hookes's law: https://brainly.com/question/3355345