Respuesta :

abiolaraymond1995

Answer:

0.605 molal

Explanation:

molality is the amount of solute in a particular mass of solvent.

lets calculate the amount of benzene solute.

mass of benzene= 13.3g

molar mass of C6H6= 12*6 +1*6 =72+7=78g/mol

amount of benzene= mass/molar mass

                           =13.3/78

                          =0.1705mol

molality= amount of solute/mass of solvent in kg

mass of solvent=282g=0.282kg

molality = 0.1705/0.282

    =0.605 molal

Cricetus

The molar concentration of benzene will be "0.605 molal".

Given:

Mass of benzene,

  • 13.3 g

Mass of solvent,

  • 282 g, or 0.282 kg

Now,

The Molar mass of [tex]C_6H_6[/tex],

= [tex]12\times 6+1\times 6[/tex]

= [tex]78 \ g/mol[/tex]

The amount of benzene will be:

= [tex]\frac{mass}{molar \ mass}[/tex]

= [tex]\frac{13.3}{78}[/tex]

= [tex]0.1705 \ mol[/tex]

hence,

→ Molality = [tex]\frac{Amount \ of \ solute}{Mass \ of \ solvent}[/tex]

                 = [tex]\frac{0.1705}{0.282}[/tex]

                 = [tex]0.605 \ molal[/tex]

Thus the answer above is right.

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