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A cylinder of compressed gas has a pressure of 488.2 kPa. The next day the cylinder of gas has a
pressure of 468 kPa and its temperature is 8*C. What was the temperature the previous day?

Respuesta :

MathPhys

Answer:

20 °C

Explanation:

Ideal gas law:

PV = nRT

Rearranging:

P / T = nR / V

Since n, R, and V are constant:

P₁ / T₁ = P₂ / T₂

488.2 kPa / T = 468 kPa / 281.15 K

T = 293.29 K

T = 20.1 °C

Rounded, the temperature was 20 °C.

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