Answer: The volume of stock solution needed is 90 mL
Explanation:
To calculate the molarity of the diluted solution, we use the equation:
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1\text{ and }V_1[/tex] are the molarity and volume of the stock sulfuric acid solution
[tex]M_2\text{ and }V_2[/tex] are the molarity and volume of diluted sulfuric acid solution
We are given:
[tex]M_1=6.0M\\V_1=?mL\\M_2=1.2M\\V_2=450mL[/tex]
Putting values in above equation, we get:
[tex]6.0\times V_1=1.2\times 450\\\\V_1=\frac{1.2\times 450}{6.0}=90mL[/tex]
Hence, the volume of stock solution needed is 90 mL
