ANSWER NEEDED FAST 15 POINTS
WILL GIVE BRAINLIEST

How many grams of oxygen are required to burn 60 grams of ethane gas, C2H6?
2 C2H6 (g) + 7 O2(g) → 4 CO2 (g) + 6 H2O (g)

____grams

Respuesta :

Answer:

224 grams of O₂

Explanation:

This is the reaction:

2 C₂H₆ (g) + 7 O₂(g) → 4 CO₂ (g) + 6 H₂O (g)

2 moles of ethene react with 7 moles of oxygen.

Let's convert the ethene's mass into moles (mass / molar mass)

60 g / 30 g/m = 2 mol

So, if 2 moles of ethene must react with 7 moles of O₂ and we have 2 moles, obviously we would need 7 moles of oyxgen.

Let's convert the moles to mass ( mol . molar mass)

7 m . 32 g/m = 224 grams

Answer: Mass of O2 is 224g

Explanation:

From the equation of the reaction, Ethane to oxygen is 2 to 7

While the molar masses respectively gives 30 and 32 g/mol

2 moles of methane gives 7 moles of O2;

60g/30=2moles for methane gives x/32 for O2;

Cross multiplying yields

7 x 2 = 2 x mass of O2/32

14 = 2x/32

Final answer gives 224 grams of oxygen