Respuesta :
Answer:
Train A is faster by a factor of 1.01
Step-by-step explanation:
Given:
Train A:
Distance = 175 Miles
Time = 4 Hours
Train B:
y=43.5x
To Find:
which train travels at a faster rate in by what factor =?
Solution:
The speed of the train A = [tex]\frac{Distance}{time}[/tex]
The speed of train A =[tex]\frac{175}{4}[/tex]
The speed of train A = 43.75 miles per hour
Speed of the train B is the slope of the given line
The standard equation of the slope of the line is
y = mx+b
where m is the slope
and we are given with
y = 43.5x
So comparing with the standard equation
m = 43.5
Hence the speed of train B is 43.5 miles per hours
Train A travels faster
[tex]Rate =\frac{\text{speed of train A}}{\text {Speed of train B}}[/tex]
[tex]rate = \frac{43.75}{43.5}[/tex]
rate =1.01
Answer:
Train A is faster by a factor of 1.01
Step-by-step explanation:
Here is what's given:
Train A has a distance of 175 miles. The time is 4 hours
Train B is y=43.5x
The speed of train A = 43.75 miles per hour
Speed of the train B is the slope of the given line. The standard equation of the slope of the line is y = mx+b
Where m is the slope and we are given with y = 43.5x.
After comparing with the standard equation we get m = 43.5
Therefore the speed of train B is 43.5 miles per hours
Train A travels faster at a rate of 1.01 mph