train a travel 175 miles in a four hours. for train b y=43.5x represents its rate of speed over the same 4 hours which train travels at a faster rate in by what factor?

Train A is faster by factor of .20

Train A is faster by a factor of 1.01

Train b is faster by a factor of .20

Train b is faster by a factor of 1.01

Respuesta :

Answer:

Train A is faster by a factor of 1.01

Step-by-step explanation:

Given:

Train A:

Distance = 175 Miles

Time = 4 Hours

Train B:

y=43.5x

To Find:

which train travels at a faster rate in by what factor  =?

Solution:

The speed of the train A = [tex]\frac{Distance}{time}[/tex]

The speed of train A  =[tex]\frac{175}{4}[/tex]

The speed of train A = 43.75 miles per hour

Speed of the train B is the slope of the given line

The standard equation of the slope of the line is

y = mx+b

where m is the slope

and we are given with

y = 43.5x

So comparing with the standard equation

m = 43.5

Hence the speed of train B is 43.5  miles per hours

Train A travels faster

[tex]Rate =\frac{\text{speed of train A}}{\text {Speed of train B}}[/tex]

[tex]rate = \frac{43.75}{43.5}[/tex]

rate  =1.01

Answer:

Train A is faster by a factor of 1.01

Step-by-step explanation:

Here is what's given:

Train A has a distance of 175 miles. The time is 4 hours

Train B is y=43.5x

The speed of train A = 43.75 miles per hour

Speed of the train B is the slope of the given line. The standard equation of the slope of the line is y = mx+b

Where m is the slope and we are given with y = 43.5x.

After comparing with the standard equation we get m = 43.5

Therefore the speed of train B is 43.5 miles per hours

Train A travels faster at a rate of 1.01 mph