Answer:
34.35464 m/s
Explanation:
q = Charge of electron = [tex]1.6\times 10^{-19}\ C[/tex]
E = Electric field = 0.08 N/C
s = Displacement = [tex]4.2\times 10^{-8}\ m[/tex]
m = Mass of electron = [tex]9.11\times 10^{-31}\ kg[/tex]
Electrical force is given by
[tex]F=qE[/tex]
Work done is given by
[tex]W=Fs\\\Rightarrow W=qEs[/tex]
Work done is also given by the kinetic energy
[tex]\dfrac{1}{2}mv^2=qEs\\\Rightarrow v=\sqrt{\dfrac{2qEs}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\times 0.08\times 4.2\times 10^{-8}}{9.11\times 10^{-31}}}\\\Rightarrow v=34.35464\ m/s[/tex]
The velocity of the electron is 34.35464 m/s
