Answer:
F = -11199.63 N
Explanation:
given,
mass of the brick = 12 Kg
height of the fall, h = 1.9 m
thickness of the carpet = 2 cm = 0.02 m
average force = ?
velocity of brick just before hitting mat
[tex] v = \sqrt{2gh}[/tex]
[tex]v =\sqrt{2\times 9.81\times 1.9}[/tex]
v = 6.11 m/s
velocity of brick just before hitting ground= 6.11 m/s
final velocity = 0 m/s
using equation of motion for acceleration calculation.
v² = u² + 2 a s
0² = 6.11² + 2x a x 0.02
[tex]a = -\dfrac{6.11^2}{0.04}[/tex]
a =-933.3025 m/s²
now, average force is equal to
F = m a
F = 12 x (-933.3025)
F = -11199.63 N
negative sign represent the decelerating force.
