Answer:
Viruses are 2 times of the bacteria.
Step-by-step explanation:
Given:
Number of viruses = [tex]2\times 10^9[/tex]
Number of bacteria = [tex]1\times 10^9[/tex]
We have to found how many times viruses are greater than the bacteria.
To find how many times,we can divide both the numbers to compare its values.
Lets
Numerator = Number of viruses
Denominator = Number of bacteria
Dividing both we have,
⇒ [tex]\frac{2\times 10^9}{1\times 10^9}[/tex]
⇒ [tex]2\times 10^(^9^-^9)[/tex] ...[tex]\frac{ab^x}{cb^y}=\frac{ab^x^-^y}{c}[/tex]
⇒ [tex]2\times 10^0[/tex] ...[tex]a^0=1[/tex]
⇒ [tex]2[/tex]
So the viruses are 2 times of the bacteria.
