Respuesta :
Answer: The mass of cryolite produced in the reaction is 1181.8 g
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Given mass of aluminium oxide = 287 g
Molar mass of aluminium oxide = 102 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of aluminium oxide}=\frac{287g}{102g/mol}=2.814mol[/tex]
The given chemical reaction follows:
[tex]6NaOH+Al_2O_3+12HF\rightarrow 2Na_3AlF_6+9H_2O[/tex]
By Stoichiometry of the reaction:
1 mole of aluminium oxide produces 2 moles of cryolite
So, 2.814 moles of aluminium oxide will produce = [tex]\frac{2}{1}\times 2.814=5.628mol[/tex] of cryolite
Now, calculating the mass of cryolite by using equation 1:
Moles of cryolite = 5.628 moles
Molar mass of cryolite = 210 g/mol
Putting values in equation 1, we get:
[tex]5.628mol=\frac{\text{Mass of cryolite}}{210g/mol}\\\\\text{Mass of cryolite}=(5.628mol\times 210g/mol)=1181.8g[/tex]
Hence, the mass of cryolite produced in the reaction is 1181.8 g
