Answer:
4 : 2
Step-by-step explanation:
The two triangles Δ ABC and Δ A'B'C' are similar.
Here, ∠ A = ∠ A' = 104°, ∠ B = ∠ B' = 50° and ∠ C = ∠ C' = 26°.
Now, the length of AB and the length of A'B' are 4 cm and 2 cm respectively.
Again, the length of BC and the length of B'C' are 9 cm and 4.5 cm respectively.
Therefore, [tex]\frac{AB}{A'B'} = \frac{BC}{B'C'} = \frac{CA}{C'A'} = \frac{4}{2} = \frac{9}{4.5} = 2[/tex]
Hence, the ratio of the corresponding side lengths is 4 : 2. (Answer)