The perimeter of rectangle is 25.13 feet
Solution:
Given that,
width of a rectangle = [tex]4\frac{1}{6} \text{ feet }[/tex]
Convert the mixed fraction to improper fraction
[tex]\rightarrow 4\frac{1}{6} = \frac{6 \times 4 + 1}{6} = \frac{25}{6}[/tex]
Therefore,
[tex]\text{width of rectangle } = \frac{25}{6} \text{ feet }[/tex]
Area of rectangle = 35 feet
The area of rectangle is given by formula:
[tex]area = length \times width[/tex]
Substituting the given values, we get
[tex]35 = length \times \frac{25}{6}\\\\length = 35 \times \frac{6}{25} = \frac{42}{5}[/tex]
Thus we get,
[tex]\text{length of rectangle } = \frac{42}{5} \text{ feet }[/tex]
The perimeter of rectangle is given as:
perimeter = 2(length + width)
[tex]perimeter = 2(\frac{42}{5} + \frac{25}{6})\\\\perimeter =2(8.4+4.167)\\\\perimeter = 2(12.567)\\\\perimeter = 25.13[/tex]
Thus perimeter of rectangle is 25.13 feet
