Answer:
Explanation:
Given
Diameter of CD [tex]d=12.70\ cm[/tex]
radius [tex]r=6.35\ cm[/tex]
mass of CD [tex]m=16.30\ gm[/tex]
Tangential velocity [tex]v_t=1.150\ m/s[/tex]
music detected at [tex]r'=20.90\ mm=2.090\ cm[/tex]
Moment of Inertia of disc [tex]I=\frac{mr^2}{2}[/tex]
[tex]I=\frac{16.30\times 10^{-3}\times (6.35\times 10^{-2})^2}{2}[/tex]
[tex]I=6.572\times 10^{-5} kg-m^2[/tex]
Work done is equal to change in kinetic Energy of CD
[tex]W=\Delta K[/tex]
[tex]W=\frac{1}{2}I\omega_f^2-\frac{1}{2}I\omega_i^2[/tex]
where [tex]\omega =[/tex]angular velocity
[tex]v_t=\omega \times r[/tex]
[tex]W=\frac{1}{2}\times 6.572\times 10^{-5}\left ( \left ( \frac{1.15}{0.0209}\right )^2-0\right )[/tex]
[tex]W=0.0994\ J[/tex]
