Answer:
5 ft/s²
Explanation:
u = Initial velocity = 100 ft/s
v = Final velocity = 0
s = Displacement = 1000 ft
a = Acceleration
From equation of motion
[tex]v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{0^2-100^2}{2\times 1000}\\\Rightarrow a=-5\ ft/s^2[/tex]
[tex]1\ ft/s^2=0.3048\ m/s^2\\\Rightarrow 5\ ft/s^2=5\times 0.3048\ m/s^2=1.524\ m/s^2[/tex]
The airplane's deceleration is 5 ft/s² or 1.524 m/s²
