Respuesta :

Answer: The mass percent of ethylene glycol in solution is 14.2 %

Explanation:

We are given:

Molarity of ethylene glycol solution = 2.45 M

This means that 2.45 moles of ethylene glycol is present in 1 L or 1000 mL of solution.

  • To calculate the mass of solution, we use the equation:

[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]

Density of solution = 1.07 g/mL

Volume of solution = 1000 mL

Putting values in above equation, we get:

[tex]1.07g/mL=\frac{\text{Mass of solution}}{1000mL}\\\\\text{Mass of solution}=(1.07g/mL\times 1000mL)=1070g[/tex]

  • To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Moles of ethylene glycol = 2.45 moles

Molar mass of ethylene glycol = 62 g/mol

Putting values in above equation, we get:

[tex]2.45mol=\frac{\text{Mass of ethylene glycol}}{62g/mol}\\\\\text{Mass of ethylene glycol}=(2.45mol\times 62g/mol)=151.9g[/tex]

  • To calculate the mass percentage of ethylene glycol in solution, we use the equation:

[tex]\text{Mass percent of ethylene glycol}=\frac{\text{Mass of ethylene glycol}}{\text{Mass of solution}}\times 100[/tex]

Mass of solution = 1070 g

Mass of ethylene glycol = 151.9 g

Putting values in above equation, we get:

[tex]\text{Mass percent of ethylene glycol}=\frac{151.9g}{1070g}\times 100=14.2\%[/tex]

Hence, the mass percent of ethylene glycol in solution is 14.2 %

dsdrajlin

The mass percent of ethylene glycol in a 2.45 M aqueous solution, whose density is 1.07, is 14.2%.

First, we will calculate the mass of ethylene glycol in 1 L of the solution. We will consider that:

  • There are 2.45 moles of ethylene glycol per liter of solution.
  • The molar mass of ethylene glycol is 62.07 g/mol.

[tex]1 L Solution \times \frac{2.45molEG}{1LSolution} \times \frac{62.07gEG}{1molEG} = 152gEG[/tex]

Now, we will calculate the mass of 1 L (1000 mL) of the solution, considering its density is 1.07 g/mL.

[tex]1000mL \times \frac{1.07g}{mL} = 1070g[/tex]

There are 152 g of ethylene glycol in 1070 g of solution. The mass percent of ethylene glycol is:

[tex]\% EG = \frac{152g}{1070g} \times 100\% = 14.2\%[/tex]

The mass percent of ethylene glycol in a 2.45 M aqueous solution, whose density is 1.07, is 14.2%.

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