Respuesta :
Answer:
1. For 0.11 m [tex]FeBr_3[/tex] : Lowest boiling point
2. For 0.15 [tex]CuBr_2[/tex]
: Second highest boiling point
3. For 0.24 [tex]AgNO_3[/tex]
: Third highest boiling point
4. 0.51 m glucose : Highest boiling point
Explanation:
Elevation in boiling point:
[tex]\Delta T_b=ik_b\times m[/tex]
where,
[tex]T_b[/tex] = change in boiling point
i= vant hoff factor
[tex]k_b[/tex] = boiling point constant
m = molality
1. For 0.11 m [tex]FeBr_3[/tex]
[tex]FeBr_3\rightarrow Fe^{3+}+3Br^{-}[/tex]
, i= 4 as it is a electrolyte and dissociate to give 4 ions and concentration of ions will be [tex]1\times 0.11+3\times 0.11=0.44[/tex]
2. For 0.15 [tex]CuBr_2[/tex]
[tex]CuBr_2\rightarrow Cu^{2+}+2Br^{-}[/tex]
, i= 3 as it is a electrolyte and dissociate to give 3 ions, concentration of ions will be [tex]1\times 0.15+2\times 0.15=0.45[/tex]
3. For 0.24 [tex]AgNO_3[/tex]
[tex]AgNO_3\rightarrow Ag^{+}+NO_3^{-}[/tex]
, i= 2 as it is a electrolyte and dissociate to give 2 ions, concentration of ions will be [tex]1\times 0.24+1\times 0.24=0.48[/tex]
4. 0.51 m glucose
i= 1 as it is a non electrolyte and does not dissociate to give ions, concentration will be [tex]1\times 0.51=0.51[/tex]
Thus as boiling point depends on the concentration of solutes, the solution having highest concentration will have highest boiling point.
