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Two rockets are lauched at the same time, but from different heights. The height y in feet of one rocket after t seconds is given by y = -16t² + 150t + 5. The height of the other rocket is given by y = -16t² + 160t. After how many second are the rockets at the same height?

Respuesta :

Answer:

0.5 seconds

Step-by-step explanation:

Two rockets are launched at the same time, but from different heights.

[tex]y = -16t^2+ 150t + 5[/tex]

[tex]y = -16t^2 + 160t[/tex]

when the heights are same then y are equal. So equation both equations and solve for t

[tex]-16t^2+ 150t + 5= -16t^2+ 160t[/tex]

Add -16t^2 on both sides

[tex]+ 150t + 5=160t[/tex]

Subtract 150 t from both sides

[tex]5=10t[/tex]

Divide 10 on both sides

t=0.5 seconds

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