Answer:
F = -1.604x10⁻⁸ N
Explanation:
The Coulomb force (F) of repulsion between nearest-neighbor O²⁻ ions in CaO can be calculated using the next equation:
[tex] F = K frac{(Z_{Ca^{2+}})(Z_{O^{2-}})(e^{-})^{2}}{r^{2}} [/tex]
where K: is the coulomb's constant, Z: is the charge of the Ca²⁺ and O²⁻ ions, e⁻: is the electron's charge, and r: is the distance between the nuclei of the two ions.
Having that:
The Coulomb force (F) of repulsion is:
[tex] F = 9\cdot 10^{9} N*m^{2}*C^{-2} \frac{(2+)(2-)(1.602\cdot 10^{-19}C)^{2}}{(2.4\cdot 10^{-10} m)^{2}} = -1.604 \cdot 10^{-8} N [/tex]
Hence, the Coulomb force of repulsion between the two ions in CaO is -1.604x10⁻⁸ N.
I hope it helps you!
The repulsive force between the ions is 1.6 x 10⁻⁸ N.
The repulsive force between the ions is calculated by applying Coulomb's law as shown below;
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
where;
The magnitude of the repulsive force is calculated as follows;
[tex]F = \frac{9\times 10^9 \times (2\times 1.6\times 10^{-19})^2}{(240 \times 10^{-12})^2 } \\\\F = 1.6 \times 10^{-8} \ N[/tex]
Thus, the repulsive force between the ions is 1.6 x 10⁻⁸ N.
Learn more about Coulomb's law here: https://brainly.com/question/24743340
