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A four-lane divided multilane highway (two lanes in each direction) in rolling terrain has five access points per mile and 11-ft lanes with a 4-ft shoulder on the right side and 2-ft shoulder on the left. The peak-hour factor is 0.84 and the traffic stream has a heavy vehicle adjustment factor of 0.847. If the analysis flow rate is 1250 pc/h/ln, what is the peak-hour volume? 976 veh/h 1345 veh/h 1389 veh/h 1779 veh/h

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danishmallick97

Answer:

v = 1779 veh/h

Explanation:

We will calculate the peak hour volume by using the following formula:-

Vp = v / ( PHF)(N)(Fg)(Fhv)

here,

1. v is the peak hour volume

2. vp is the analysis flow rate

3. PHF is the peak hour factor

4. N is the number of lanes

5. Fg is the grade adjustment factor which is 0.99 for rolling terrain > 1200 pc/h/ln

6. Fhv is the heavy vehicle adjustment factor

vp = v / (PHF) (N) (Fg) (Fhv)

1250 = v / (0.84)(2)(1)(0.847)

v = 1779 veh/h

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