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A pure organic amide product (2.85 g) which has a molecular weight of 285.34 g/mol was fully dissolved in 20mL of the boiling solvent, hexanes. This organic amide product then underwent a recrystallization when the solvent was cooled to 0° C. The recrystallized organic product (2.62 grams) was obtained after vacuum filtration. What is the solubility of the organic amide product in the solvent, hexanes, at 0° C?

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nandhini123

Answer:

The solubility of the organic amide product in the solvent hexane is 0.0403 moles/L at 0° C

Explanation:

When 2.85gm dissolved in 20ml of boiling solvent

After re crystallization 2.62gm was obtained

so, that the dissolved amount at 0° C is

2.85 - 2.62

= 0.23 gm in 20ml hexane

Mole of amide [tex]= \frac{0.23}{285.34} moles[/tex]

Solubility [tex]= \frac{0.23}{285.34} \times \frac{1000}{20}[/tex]

               = 0.0403 moles/L

Therefore, the solubility of the organic amide product in the solvent hexane is 0.0403 moles/L at 0° C