Answer:
a) speed of wind = 39.48 mph
b) direction of wind = 185.2 dgree
Step-by-step explanation:
Given data:
sir speed is 150 mph
angle of course with ground is 72
ground speed is 130 mph
angle of plane = 58
angle between the angle of plane and course angle is [tex]= 72^o - 58^o = 14^o[/tex]
from cosine formula speed of wind can be calculate as
[tex]c^2 = 150^2 + 30^2 - 2\times (150)(130) cos 14[/tex]
[tex]c^2 = 1558.47[/tex]
c = 39.48
angle of wind can be calculate by using sin rule
[tex]\frac{39.48}{sin 14} = \frac{130}{sin \theta}[/tex]
solving for theta
[tex]\theta = 52.81^o[/tex]
the direction of wind [tex]= 180+58-52.81 = 185.2^o[/tex]